Q. Velocity at mean position of a particle S.H.M. is $v,$ they velocity of the particle at a distance equal to half of the amplitude
A) $4v$
B) $2v$
C) $\frac{\sqrt{3}}{2}v$
D) $\frac{\sqrt{3}}{4}v$
Explanation
(c) Velocity in mean position $v = a\omega,$ velocity at a distance of half amplitude
$v^{'} = \omega\sqrt{a^{2} - y^{2}} = \omega\sqrt{a^{2} - \frac{a^{2}}{4}} = \frac{\sqrt{3}}{2}a\omega = \frac{\sqrt{3}}{2}v$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.