When the displacement is half of the amplitude, then when fraction of the total energy of a simple harmonic oscillator is kinetic?

Question

Dr. Abubacker · Accepted Answer

(b) Kinetic energy, $E_{k} = \frac{1}{2}m\left( a^{2} - y^{2} \right)$
$= \frac{1}{2}m\left( a^{2} - \frac{a^{2}}{4} \right) = \frac{1}{2}m\omega^{2}a^{2}\frac{3}{4}$
Total energy, $E = \frac{1}{2}m\omega^{2}a^{2}$
So $E_{k}/E = 3/4$

Q. When the displacement is half of the amplitude, then when fraction of the total energy of a simple harmonic oscillator is kinetic?

Explanation

Reviewed by Dr. Abubacker

Want more practice?