Q. The displacement y in cm is given in terms of time t sec by the equation y = 3 sin 314t + cos314t The amplitude of SHM is

A) 7 cm
B) 3 cm
C) 4 cm
D) 5 cm
Explanation

(d) $Y = 3\sin{31\ 4t + 4\cos{31\ 4t}}$
$= r\cos\theta\sin{314t + r\sin\theta}\cos 314t$
$= r\sin{(314\ t + \theta)}$ …(i)
Where $r\cos{\theta = 3}$ and $r\sin\theta = 4$
$\therefore\ \ \ r^{2}\left( \cos^{2}\theta + \sin^{2}\theta \right) = 3^{2} + 4^{2} = 25$
or $r = 5$ cm

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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