Two simple harmonic motions are represented by $y_{1} = 4\sin{(4\pi t + \frac{\pi}{2})}$ and $y_{2} = 3\cos{(4\pi t)}.$ The resultant amplitude is

Question

Dr. Abubacker · Accepted Answer

(a) $y_{1} = 4\sin{\left( 4\pi t + \frac{\pi}{2} ight) = 4\cos{4\pi t}}$
$y_{2} = 3\cos{(4\pi t) = 3\cos{4\pi t}}$
The phase difference $= 0,$ both are along the same line
$	herefore A^{2} = 4^{2} + 3^{2} + 2 	imes 4 	imes 3\cos{0{^\circ}}$
$A^{2} = (4 + 3)^{2} \Rightarrow A = 7$
The resultant amplitude is 7 units

Q. Two simple harmonic motions are represented by $y_{1} = 4\sin{(4\pi t + \frac{\pi}{2})}$ and $y_{2} = 3\cos{(4\pi t)}.$ The resultant amplitude is

Explanation

Reviewed by Dr. Abubacker

Want more practice?