The equation of SHM is given by $x = 3\sin{20\pi t + 4\cos{20\pi t}}$ Where $x$ is in cm and $t$ is I second. The amplitude is

Question

Dr. Abubacker · Accepted Answer

(c) $x = 3\sin{20\pi t + 4\cos{20\pi t}}$
$= 5\left\lbrack \frac{3}{5}\sin{20\pi t + \frac{4}{5}}\cos{20\pi t} ightbrack$
$= 5\lbrack\cos	heta\sin{20\pi t + \sin{	heta\cos{20\pi t}}}brack$
$= 5\sin{(20\pi t + 	heta)}$
It is a SHM of amplitude 5 cm.

Q. The equation of SHM is given by $x = 3\sin{20\pi t + 4\cos{20\pi t}}$ Where $x$ is in cm and $t$ is I second. The amplitude is

Explanation

Reviewed by Dr. Abubacker

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