Q. For a particle in SHM, if the amplitude of the displacement is $a$ and the amplitude of velocity is $v'$ the amplitude of acceleration is
A) $va$
B) $\frac{v^{2}}{a}$
C) $\frac{v^{2}}{2a}$
D) $\frac{v}{a}$
Explanation
(b) $v_{\max} = a\omega$ and
Maximum acceleration = $\omega^{2}a$
= $\left( \frac{v}{a} \right)^{2}a = \frac{v^{2}}{a}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.