Q. The time period of a simple pendulum in a lift descending with constant acceleration $g$ is
A) $T = 2\pi\sqrt{\frac{l}{g}}$
B) $T = 2\pi\sqrt{\frac{l}{2g}}$
C) Zero
D) Infinite
Explanation
(d) This is the case of freely falling lift and in free fall of lift effective $g$ for pendulum will be zero. So $T = 2\pi\sqrt{\frac{l}{0}} = \infty$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.