Q. A particle executing a simple harmonic motion has a period of 6 s. The time taken by the particle to move from the mean position to half the amplitude, starting from the mean position is
A) $\frac{1}{4}$ s
B) $\frac{3}{4}$ s
C) $\frac{1}{2}$ s
D) $\frac{3}{2}$ s
Explanation
(c) $y = A\sin\left( \frac{2\pi}{T} \right)t$
$\frac{A}{2} = A\sin\left( \frac{2\pi}{T} \right)t = \frac{2\pi}{T}t = \frac{\pi}{6}$
Time period $t = \frac{T}{12} = \frac{6}{12} = \frac{1}{2}$ s
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.