For a particle executing SHM the displacement $x$ is given by $\ x = A\cos{\omega t}$. Identify the graph which represents the variation of potential energy (PE) as a function of time $t$ and displacement $x$. [image:14_image13.emf]

Question

Dr. Abubacker · Accepted Answer

(a) Potential energy is minimum (in the case zero) at mean position ($x = 0$) and maximum at extreme positions ($x = \pm A$). At time $t = 0,\ x = A$. Hence, PE should be maximum. Therefore, graph I is correct. Further in graph III, PE is minimum at $x = 0$. Hence, this is also correct.

Q. For a particle executing SHM the displacement $x$ is given by $\ x = A\cos{\omega t}$. Identify the graph which represents the variation of potential energy (PE) as a function of time $t$ and displacement $x$.

Explanation

Reviewed by Dr. Abubacker

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