Q. Two pendulums have time period T and 5T/4. They start SHM at the same time from the mean position. What will be the phase difference between then after the bigger pendulum completed one oscillation?
A) $45^{0}$
B) $90^{0}$
C) $60^{0}$
D) $30^{0}$
Explanation
(b) When bigger pendulum of time period ($5T/4$) completes one vibration, the smaller pendulum will complete (5/4) vibrations. It means the smaller pendulum will be leading the bigger pendulum by phase $T/4$ sec$= \pi/2$ rad $= 90{^\circ}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.