Two springs with spring constants $K_{1} = 1500\ N/m$ and $K_{2} = 3000N/m$ are stretched by the same force. The ratio of potential energy stored in spring will be

Question

Dr. Abubacker · Accepted Answer

(a) $U = \frac{F^{2}}{2K} \Rightarrow U \propto \frac{1}{K} \Rightarrow \frac{U_{1}}{U_{2}} = \frac{K_{2}}{K_{1}} = 2$

Q. Two springs with spring constants $K_{1} = 1500\ N/m$ and $K_{2} = 3000N/m$ are stretched by the same force. The ratio of potential energy stored in spring will be

Explanation

Reviewed by Dr. Abubacker

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