(d) $T \propto \frac{1}{\sqrt{k}} \Rightarrow \frac{T_{2}}{T_{1}} = \sqrt{\frac{k_{1}}{k_{2}}} = \sqrt{\frac{k}{4k}} = \frac{1}{2} \Rightarrow T_{2} = \frac{T_{1}}{2}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.