For a simple pendulum, the graph between $T^{2}$ and $L$ is

Question

Dr. Abubacker · Accepted Answer

(a) $T = 2\pi\sqrt{\frac{L}{g}}$
[image:14_image63.emf]
or $T \propto \sqrt{L}\ \ \ or\ \ \ \ T^{2} \propto L$
It is linear relation between $T^{2}\ and\ l$ hence the graph between $T^{2}and\ L$ is a straight line passing through the origin.

Q. For a simple pendulum, the graph between $T^{2}$ and $L$ is

Explanation

Reviewed by Dr. Abubacker

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