Q. A pendulum is made to hang from the ceiling of an elevator. It has period of $T$ s (for small angles). The elevator is made to accelerate upwards with $10m/s^{2}.$ The period of the pendulum now will be (assume $g = 10m/s^{2}$)

A) $T\sqrt{2}$
B) Infinite
C) $T/\sqrt{2}$
D) Zero
Explanation

(c) $T = 2\pi\sqrt{\frac{l}{g_{net}}}$
$g_{net} = g + a = 10 + 10$
$g_{net} = 20m/s^{2}$
$T^{'} = \frac{T}{\sqrt{2}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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