Q. In a simple harmonic oscillator has got a displacement of $0.02\ m$ and acceleration equal to $2.0ms^{- 2}$ at any time, the angular frequency of the oscillator is equal to
A) $10rad\ s^{- 1}$
B) $0.1rad\ s^{- 1}$
C) $100rad\ s^{- 1}$
D) $1rad\ s^{- 1}$
Explanation
(a) $\omega = \sqrt{\frac{Acceleration}{Displacement}} = \sqrt{\frac{2.0}{0.02}} = 10\ rad\ s^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.