Q. A particle moving along the $x$-axis executes simple harmonic motion, then the force acting on it is given by

A) $- A\ Kx$
B) $A\cos{(Kx)}$
C) $A\exp{( - Kx)}$
D) $A\ Kx$
Explanation

(a) For S.H.M. $F = - kx$
$\therefore$ Force $=$ Mass $\times$ Acceleration $\propto - x$
$\Rightarrow F = - Akx;$ where $A$ and $k$ are positive constants

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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