Q. For a particle executing SHM the displacement $x$ is given by $x = A\cos{\omega t.\ }$ Identify the graph which represents the variation of potential energy (PE) as a function of time and displacement$\ x$.

A) I,III
B) II,III
C) I,IV
D) II,IV
Explanation

(a) Potential energy is minimum (in this case zero) at mean position $(x = 0)$ and minimum at extreme position $(x = \pm A)$
At time$t = 0,\ x = A$, hence potential should be maximum. Therefore graph. I is correct. Further in graph III. Potential energy is minimum at$x = 0$, hence this is also correct.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Oscillations MCQs