Q. One-fourth length of a spring of force constant $K$ is cut away. The force constant of the remaining spring will be
A) $\frac{3}{4}K$
B) $\frac{4}{3}K$
C) $K$
D) $4\ K$
Explanation
(b) By using $K \propto \frac{1}{l}$
Since one fourth length is cut away so remaining length is $\frac{3}{4}th,$ hence $k$ becomes $\frac{4}{3}$ times $i.e.,\ K^{'} = \frac{4}{3}K$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.