A pendulum clock is placed on the moon, where object weighs only one-sixth as much as on earth, how many seconds the clock tick out in an actual time of 1 minute the clock keeps good time on earth?

Question

Dr. Abubacker · Accepted Answer

(b) $T^{'} = 2\pi\sqrt{l/(g/6)} = \sqrt{6}T$ Hence, the clock will tick in one minute
$= 60/\sqrt{6} = 24.5$ times

Q. A pendulum clock is placed on the moon, where object weighs only one-sixth as much as on earth, how many seconds the clock tick out in an actual time of 1 minute the clock keeps good time on earth?

Explanation

Reviewed by Dr. Abubacker

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