Q.
A wooden block performs SHM on a frictionless surface with frequency, $v_{0}.$ The block carries a change $+ Q$ on its surface. If now a uniform electric field $\overrightarrow{E}$ is switched-on as shown, then SHM of the block will be
A) Of the same frequency and with shifted mean position
B) Of the same frequency and with the same mean position
C) Of changed frequency and with shifted mean position
D) Of changed frequency and with the same mean position
Explanation
(a) The frequency will be same $f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}$ but due to the constant $qE$ force, the equilibrium position gets shifted by $\frac{qE}{K}$ in forward direction. So Sol. will be (a)
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.