(d) $x_{1} + x_{2} = A\ and\ k_{1}x_{1} = k_{2}x_{2}\ \ \ \ or\ \ \ \frac{x_{1}}{x_{2}} = \frac{k_{2}}{k_{1}}$ Solving these equations, we get $x_{1} = \left( \frac{k_{2}}{k_{1} + k_{2}} \right)A$
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Ph.D. in Physics with 19+ years of teaching experience.