Q. A $1.00 \times 10^{- 20}kg$ particle is vibrating with simple harmonic motion with a period of $1.00 \times 10^{- 5}s$ and a maximum speed of $1.00 \times 10^{3}m/s.$ The maximum displacement of the particle is
A) $1.59\ mm$
B) $1.00\ m$
C) $10\ m$
D) None of these
Explanation
(a) $v_{\max} = a\omega = a \times \frac{2\pi}{T} \Rightarrow a = \frac{v_{\max} \times T}{2\pi}$
$A = \frac{1.00 \times 10^{3} \times (1 \times 10^{- 5})}{2\pi} = 1.59\ mm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.