(d) In S.H.M. $v = \omega\sqrt{a^{2} - y^{2}}\ $and$\ a = - \omega^{2}y$ when $y = 0$ $\Rightarrow v_{\max} = a\omega\ $and$\ a_{\min} = 0$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.