Q. The period of oscillation of a simple pendulum of length $l$ suspended from the roof of a vehicle, which moves without friction down an inclined plane of inclination $\alpha$ is given by
A) $2\pi\sqrt{\frac{1}{g\cos\alpha}}$
B) $2\pi\sqrt{\frac{1}{g\sin\alpha}}$
C) $2\pi\sqrt{\frac{l}{g}}$
D) $2\pi\sqrt{\frac{1}{g\tan\alpha}}$
Explanation
(a) Time period $T = 2\pi\sqrt{\frac{l}{g_{eff}}}$
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$T = 2\pi\sqrt{\frac{l}{g\cos\alpha}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.