Q. If the displacement of a particle executing SHM is given by $y = 0.30\sin{(220t + 0.64)}$ in $metre$, then the frequency and maximum velocity of the particle is
A) $35\ Hz,\ 66\ m/s$
B) $45\ Hz,\ 66\ m/s$
C) $58\ Hz,\ 113\ m/s$
D) $35\ Hz,\ 132\ m/s$
Explanation
(a) $n = \frac{\omega}{2\pi} = \frac{220}{2\pi} = 35Hz$
$v_{\max} = \omega a = 220 \times 0.30m/s = 66m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.