Q. The period of oscillation of a simple pendulum of constant length at earth surface is $T.$ Its period inside a mine is
A) Greater than $T$
B) Less than $T$
C) Equal to $T$
D) Cannot be compared
Explanation
(a) Inside the mine $g$ decreases
Hence from $T = 2\pi\sqrt{\frac{l}{g}};T\ $increase
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.