Q. When a mass $M$ is attached to the spring of force constant $k,$ then the spring stretches by $l.$ If the mass oscillates with amplitude $l,$ what will be maximum potential energy stored in the spring
A) $\frac{kl}{2}$
B) $2kl$
C) $\frac{1}{2}Mgl$
D) $Mgl$
Explanation
(b) $Mg = Kl \Rightarrow U_{\max} = \frac{1}{2}K(2l)^{2} = 2Kl$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.