Q. A particle of mass 1 kg is moving in SHM with an amplitude 0.02 m and a frequency of 60 Hz. The maximum force in newton acting on the particle is
A) $188{\ \pi}^{2}$
B) $144\pi^{2}$
C) $288\pi^{2}$
D) None of these
Explanation
(c) Maximum force$= m\omega^{2}a = m4\pi v^{2}a$
$= 1 \times 4\pi^{2} \times (60)^{2} \times 0.02 = 288\pi^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.