Q. A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of $31.4\ cm/s$. The frequency of its oscillation is
A) 3 Hz
B) 2 Hz
C) 4 Hz
D) 1 Hz
Explanation
(d) $A = 5$ cm
$V_{man} = 3.14\ cm/s$
$\Rightarrow \ \ A\omega = 31.4$
$\Rightarrow \ \ \ \ \ \ \omega = \frac{31.4}{5}$
$\Rightarrow \ \ \ \ \ 2\pi v = \frac{31.4}{5}$
$\Rightarrow \ \ \ \ \ \ \ v = \frac{31.4}{2 \times 3.14 \times 5}$ = 1 Hz
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.