Q. A particle of mass m oscillates with simple harmonic motion between points $x_{1}$ and $x_{2},$ the equilibrium position being $O.$ Its potential energy is plotted. It will be as given below in the graph
A)
B)
C)
D)
Explanation
(d) Potential energy of particle performing SHM is given by: $PE = \frac{1}{2}m\omega^{2}y^{2},\ i.e.,$ it varies parabolically such that at mean position it becomes zero and maximum at extreme positions
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.