Q. The displacement of a particle in SHM various according to the relation $x = 4\ (cos\pi\ t + sin\pi\ t)$. The amplitude of the particle is
A) -4
B) 4
C) $4\sqrt{2}$
D) 8
Explanation
(c) $R\sin{\delta = 4}$
and $R\cos{\delta = 4}$
$R = 4\sqrt{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.