Q. For a body of mass m attached to the spring, the spring factor is given by $(\omega,\ the\ angular\ frequency)$
A) $m/\omega^{2}$
B) $m\ \omega^{2}$
C) $m^{2}\omega$
D) $m^{2}\omega^{2}$
Explanation
(b) $T = 2\pi\sqrt{\frac{m}{k}}\ \ \ or\ \ \ k = \frac{4\pi^{2}}{T^{2}}m = \omega^{2}m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.