Q. Two points are located at a distance of $10\ m$ and $15\ m$ from the source of oscillation. The period of oscillation is $0.05\ sec$ and the velocity of the wave is $300\ m/sec.$ What is the phase difference between the oscillations of two points
A) $\pi$
B) $\frac{\pi}{6}$
C) $\frac{\pi}{3}$
D) $\frac{2\pi}{3}$
Explanation
(d) Wave length = velocity of wave$\ \times$ Time period
$\lambda = 300 \times 0.05 \Rightarrow \lambda = 15\ metre$
According to problem path difference between two points $= 15 - 10 = 5m$
$\therefore$ Phase difference $= \frac{2\pi}{\lambda} \times$ Path difference
$= \frac{2\pi}{15} \times 5 = \frac{2\pi}{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.