Q. A body is executing simple harmonic motion with an angular frequency $2\ rad/s.$ The velocity of the body at $20\ mm$ displacement, when the amplitude of motion is $60\ mm,$ is
A) $40\ mm/s$
B) $60\ mm/s$
C) $113\ mm/s$
D) $120\ mm/s$
Explanation
(c) $v = \omega\sqrt{(a^{2} - y^{2})} = 2\sqrt{60^{2} - 20^{2}} = 113mm/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.