Q. A particle executes SHM with a period of 8 s and amplitude 4 cm. Its maximum speed in $cms^{- 1}$, is
A) $\pi$
B) $\frac{\pi}{2}$
C) $\frac{\pi}{3}$
D) $\frac{\pi}{4}$
Explanation
(a) For a particle executing SHM
$v_{\max} = A\omega$
$= 4 \times \frac{2\pi}{T} = 4 \times \frac{2\pi}{8}$
$\ = \ \pi\ cms^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.