A pendulum bob of mass $m$ is hanging from a fixed point by a light thread of length $l.$ A horizontal speed $v_{0}$ is imparted to the bob so that it takes up horizontal position. If $g$ is the acceleration due to gravity, then $v_{0}$ is

Question

Dr. Abubacker · Accepted Answer

(b) According to the law of conservation of mechanical energy, we get
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$\frac{1}{2}mv_{0}^{2} = mgl$
$\Rightarrow v_{0} = \sqrt{2gl}$

Q. A pendulum bob of mass $m$ is hanging from a fixed point by a light thread of length $l.$ A horizontal speed $v_{0}$ is imparted to the bob so that it takes up horizontal position. If $g$ is the acceleration due to gravity, then $v_{0}$ is

Explanation

Reviewed by Dr. Abubacker

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