Q. The motion of a particle executing S.H.M. is given by $x = 0.01\sin{100\pi(t + .05)},$ where $x$ is in $metres$ and time is in seconds. The time period is
A) $0.01\ s$
B) $0.02\ s$
C) $0.1\ s$
D) $0.2\ s$
Explanation
(b) $\omega = \frac{2\pi}{T} = 100\pi \Rightarrow T = 0.02\ s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.