Q. The variation of potential energy of harmonic oscillator is as shown in figure. The spring constant is
A) $1 \times 10^{2}N/m$
B) $150\ N/m$
C) $0.667 \times 10^{2}N/m$
D) $3 \times 10^{2}N/m$
Explanation
(b) Total potential energy $= 0.04\ J$
Resting potential energy $= 0.01\ J$
Maximum kinetic energy $= (0.04 - 0.01)$
$= 0.03J = \frac{1}{2}m\ \omega^{2}a^{2} = \frac{1}{2}ka^{2}$
$0.03 = \frac{1}{2} \times k \times \left( \frac{20}{1000} \right)^{2}$
$k = 0.06 \times 2500\ N/m = 150\ N/m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.