Q. A body of mass 4 kg hangs from a spring and oscillates with a period 0.5 s on the removel of the body, the spring is shortented by
A) 6.3 cm
B) 0.63 cm
C) 6.25 cm
D) 6.3 cm
Explanation
(c) Time period $T = 2\pi\sqrt{\frac{m}{k}}$
$\because$ $mg = kx$
$\therefore$ $T = 2\pi\sqrt{\frac{x}{g}}$
$(0.5)^{2} = 4\pi^{2} \times \sqrt{\frac{x}{10}}$
$\frac{(0.5)^{2} \times 9.8}{4 \times 3.14 \times 3.14} = x$
$x = 0.0621$ m
$x = 6.2$ cm
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.