Q. A pendulum has time period $T.$ If it is taken on to another planet having acceleration due to gravity half and mass 9 times that of the earth then its time period on the other planet will be
A) $\sqrt{T}$
B) $T$
C) $T^{1/3}$
D) $\sqrt{2}\ T$
Explanation
(d) $T = 2\pi\sqrt{\frac{l}{g}} \Rightarrow T \propto \frac{1}{\sqrt{g}} \Rightarrow \frac{T_{P}}{T_{e}} = \sqrt{\frac{g_{e}}{g_{P}}} = \sqrt{\frac{2}{1}} \Rightarrow T_{P} = \sqrt{2}T_{e}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.