Q. If the length of second’s pendulum is increased by 2% How many seconds it will lose per day?
A) 3927 s
B) 3427 s
C) 3737 s
D) 864 s
Explanation
(d) $T^{'} = T\sqrt{\frac{l + 2l/100}{l}}$
$= T\left( 1 + \frac{2}{100} \right)^{1/2} = 2\left( 1 + \frac{1}{100} \right)$
$\therefore\ \ \ \ T^{'} - T = \frac{2}{100} = \frac{1}{50}s$
Therefore, loss in seconds per day
$= \frac{1/50}{2} \times 24 \times 60 \times 60 = 864\ s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.