The bob of a simple pendulum is of mass 10 g. It is suspended with a thread of 1 m. If we hold the bob so as to stretch the string horizontally and release it, what will be the tension at the lowest position? (g= 10 $ms^{- 2}$)

Question

Dr. Abubacker · Accepted Answer

(c) When the bob falls through a vertical height of 1m, the velocity acquired at the lowest point,
$v = \sqrt{2gh} = \sqrt{2 	imes 10 	imes 1} = \sqrt{20}\ ms^{- 1}$
Centrifugal force$= \frac{mv^{2}}{r} = \frac{0.01 	imes 20}{1} = 0.20\ N$
Net tension=weight+centrifugal force
$= (0.01 	imes 10 + 0.20) = 0.30\ N$

Q. The bob of a simple pendulum is of mass 10 g. It is suspended with a thread of 1 m. If we hold the bob so as to stretch the string horizontally and release it, what will be the tension at the lowest position? (g= 10 $ms^{- 2}$)

Explanation

Reviewed by Dr. Abubacker

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