A particle moves according to the law,$\ = rcos\frac{\pi t}{2.}$. The distance covered by it the time interval between t= 0 to t=3s is

Question

Dr. Abubacker · Accepted Answer

(c) When $t = 0,\ x = r\cos\frac{\pi 	imes 0}{2} = r$;
When $t = 3s,\ x = r\cos\frac{\pi 	imes 3}{2} = 0$
Here $\omega = \frac{\pi}{2}$ or $\frac{2\pi}{T} = \frac{\pi}{2}$ or $T = 4s$
$	herefore$ In 3 sec, the particle goes from one extreme to other extreme and then back to mean position. So the distance travelled $= 2r + r = 3r$

Q. A particle moves according to the law,$\ = rcos\frac{\pi t}{2.}$. The distance covered by it the time interval between t= 0 to t=3s is

Explanation

Reviewed by Dr. Abubacker

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