Q. A simple harmonic oscillator has a period of $0.01\ s$ and an amplitude of $0.2\ m.$ The magnitude of the velocity in $m\sec^{- 1}{at}$ the centre of oscillation is
A) $20\pi$
B) 100
C) $40\pi$
D) $100\pi$
Explanation
(c) At centre $v_{\max} \Rightarrow a\omega = a.\frac{2\pi}{T} = \frac{0.2 \times 2\pi}{0.01} = 40\pi$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.