Q. A spring of force constant $k$ is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of
A) $(2/3)k$
B) $(3/2)k$
C) $3k$
D) $6k$
Explanation
(b) Force constant $(k) \propto \frac{1}{Length\ of\ spring}$
$\Rightarrow \frac{K}{K_{1}} = \frac{l_{1}}{l} = \frac{\frac{2}{3}l}{l} \Rightarrow K_{1} = \frac{3}{2}K$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.