Q. Two springs, of force constants$\ k_{1}\ and\ k_{2}$, are connected to a mass $m$ as shown. The frequency of the mass is $f$. If both $k_{1}\ and\ k_{2}$ are made four times their original values, the frequency of oscillation becomes

A) $\frac{f}{2}$
B) $\frac{f}{4}$
C) $4f$
D) $2f$
Explanation

(d) $f = \frac{1}{2\pi}\ \sqrt{\frac{k_{1} + k_{2}}{m}}$
and $f^{'} = \frac{1}{2\pi}\ .2\sqrt{\frac{k_{1} + k_{2}}{m}} = 2f$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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