Q.
A body of mass 0.01 kg executes SHM about $x = 0$, under the influence of force shown in the figure The period of the SHM is
A) 1.05 s
B) 0.52 s
C) 0.25 s
D) 0.03 s
Explanation
(d) Here, $k = \frac{F}{x} = \frac{80}{0.2} = 400\ Nm^{- 1}$
$T = 2\pi\sqrt{\frac{m}{k}}$
$= 2\pi\sqrt{\frac{0.01}{400}}$
$= \frac{\pi}{100} = 0.03142\ s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.