Q. The total energy of a simple harmonic oscillator is proportional to

A) Square root of displacement
B) Velocity
C) Frequency
D) Square of the amplitude
Explanation

(d) $TE = \frac{1}{2}m\omega^{2}a^{2}$
$TE \propto a^{2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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