Q. A body of mass $1kg$ is executing simple harmonic motion. Its displacement $y(cm)$ at $t$ seconds is given by $y = 6\sin{(100t + \pi/4).}$ Its maximum kinetic energy is
A) $6\ J$
B) $18\ J$
C) $24\ J$
D) $36\ J$
Explanation
(b) So $a = 6cm,\ \omega = 100rad/s$
$K_{\max} = \frac{1}{2}m\omega^{2}a^{2} = \frac{1}{2} \times 1 \times (100)^{2} \times \left( 6 \times 10^{- 2} \right)^{2} = 18\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.