A particle has simple harmonic motion. The equation of its motion is $x = 5\sin{\left( 4t - \frac{\pi}{6} \right),}$ where $x$ is its displacement. If the displacement of the particle is 3 units, then it velocity is

Question

Dr. Abubacker · Accepted Answer

(d) From the given equation, $a = 5\ $and$\ \omega = 4$
$	herefore v = \omega\sqrt{a^{2} - y^{2}} = 4\sqrt{(5)^{2} - (3)^{2}} = 16$

Q. A particle has simple harmonic motion. The equation of its motion is $x = 5\sin{\left( 4t - \frac{\pi}{6} \right),}$ where $x$ is its displacement. If the displacement of the particle is 3 units, then it velocity is

Explanation

Reviewed by Dr. Abubacker

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